When (5k+1)^2 is divided by 5,the remainder i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) We are given the expression $(5k+1)^2$.Expanding this using the identity $(a+b)^2 = a^2 + 2ab + b^2$,we get:$(5k+1)^2 = (5k)^2 + 2(5k)(1) + (1)^2$

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(B) We are given the expression $(5k+1)^2$.Expanding this using the identity $(a+b)^2 = a^2 + 2ab + b^2$,we get:$(5k+1)^2 = (5k)^2 + 2(5k)(1) + (1)^2$$= 25k^2 + 10k + 1$$= 5(5k^2 + 2k) + 1$Here,the expression is in the form $5q + 1$,where $q = 5k^2 + 2k$ is an integer.Therefore,when $(5k+1)^2$ is divided by $5$,the remainder is $1$.

When $(5k+1)^2$ is divided by $5$,the remainder is . . . . . . .

Similar Questions

Any odd positive integer $a$ is of the form . . . . . . ,where $m$ is an integer.

The value of the terminating decimal form of $\frac{337}{125}$ is . . . . . . .

Find the $LCM(26, 91)$.

If the $HCF(a, b) = 25$,then which of the following cannot be the $LCM(a, b)$?

The number $0.01111...$ is a type of........

Vedclass Test Series

Exam Paper Generator

Online Exam Module