When an aqueous solution of copper $(II)$ sulphate is saturated with ammonia,the blue compound crystallises on evaporation. The formula of this blue compound is
- A$[Cu(NH_3)_4]SO_4 \cdot H_2O$ (square planar)
- B$[Cu(NH_3)SO_4]$ (tetrahedral)
- C$[Cu(NH_3)_6]SO_4$ (octahedral)
- D$[Cu(SO_4)(NH_3)_4]$ (octahedral)
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Similar Questions
Which of the following pairs of compounds is planar?
Difficult
View SolutionMatch List $-I$ with List $-II$:
List $-I$ List $-II$ $A$. $[PtCl_4]^{2-}$ $I$. $sp^3d$ $B$. $BrF_5$ $II$. $d^2sp^3$ $C$. $PCl_5$ $III$. $dsp^2$ $D$. $[Co(NH_3)_6]^{3+}$ $IV$. $sp^3d^2$
| List $-I$ | List $-II$ |
| $A$. $[PtCl_4]^{2-}$ | $I$. $sp^3d$ |
| $B$. $BrF_5$ | $II$. $d^2sp^3$ |
| $C$. $PCl_5$ | $III$. $dsp^2$ |
| $D$. $[Co(NH_3)_6]^{3+}$ | $IV$. $sp^3d^2$ |
$Mn^{2+}$ forms a complex with $Br^{-}$ ion. The magnetic moment of the complex is $5.92 \ B.M.$ What could not be the probable formula and geometry of the complex?
Difficult
View SolutionDiscuss the nature of bonding in the following coordination entities on the basis of valence bond theory:
$(i)$ $[Fe(CN)_6]^{4-}$
$(ii)$ $[FeF_6]^{3-}$
$(iii)$ $[Co(C_2O_4)_3]^{3-}$
$(iv)$ $[CoF_6]^{3-}$
$(i)$ $[Fe(CN)_6]^{4-}$
$(ii)$ $[FeF_6]^{3-}$
$(iii)$ $[Co(C_2O_4)_3]^{3-}$
$(iv)$ $[CoF_6]^{3-}$
Easy
View SolutionIn the formation of $K_4[Fe(CN)_6]$,the hybridisation involved is
Medium
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