When an open pipe is closed from one end, the | vedclass

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(D) Let the fundamental frequency of the open pipe be $f_o = \frac{v}{2L}$.The second overtone of an open pipe is given by $f_{o,2} = 3f_o = 3 	imes

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$300$

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(D) Let the fundamental frequency of the open pipe be $f_o = \frac{v}{2L}$.The second overtone of an open pipe is given by $f_{o,2} = 3f_o = 3 	imes \frac{v}{2L}$.Let the fundamental frequency of the closed pipe be $f_c = \frac{v}{4L}$.The third overtone of a closed pipe is the $7^{th}$ harmonic, given by $f_{c,3} = 7f_c = 7 	imes \frac{v}{4L}$.According to the problem, $f_{c,3} - f_{o,2} = 150 	ext{ Hz}$.Substituting the expressions: $\frac{7v}{4L} - \frac{3v}{2L} = 150$.$\frac{7v - 6v}{4L} = 150 \implies \frac{v}{4L} = 150 	ext{ Hz}$.Since $f_o = \frac{v}{2L} = 2 	imes \frac{v}{4L}$, we have $f_o = 2 	imes 150 = 300 	ext{ Hz}$.

When an open pipe is closed from one end, the third overtone of the closed pipe is higher in frequency by $150 \text{ Hz}$ than the second overtone of the open pipe. The fundamental frequency of the open pipe will be (Neglect end correction). (in $\text{ Hz}$)

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