Which compound of sulphur is formed in the se | vedclass

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(D) The ground state electronic configuration of sulphur $(S)$ is $[Ne] 3s^2 3p^4$.In the first excited state,one electron from the $3p$ orbital is pr

Vedclass · Accepted Answer

$SF_6$

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(D) The ground state electronic configuration of sulphur $(S)$ is $[Ne] 3s^2 3p^4$.In the first excited state,one electron from the $3p$ orbital is promoted to the $3d$ orbital,resulting in $3s^2 3p^3 3d^1$. This state allows for the formation of $SF_4$ through $sp^3d$ hybridization.In the second excited state,one electron from the $3s$ orbital is also promoted to the $3d$ orbital,resulting in $3s^1 3p^3 3d^2$. This provides six unpaired electrons for bonding.These six orbitals undergo $sp^3d^2$ hybridization to form $SF_6$ with octahedral geometry.Therefore,$SF_6$ is the compound formed in the second excited state.

Which compound of sulphur is formed in the second excited state?

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