Which of the following pairs of solutions is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For isotonic solutions,the molar concentrations must be equal: $C_{	ext{urea}} = C_{	ext{sucrose}}$.First,calculate the molarity for each option

Vedclass · Accepted Answer

$3.0 \ g \ L^{-1}$ urea and $17.19 \ g \ L^{-1}$ sucrose

Vedclass · Answer

(A) For isotonic solutions,the molar concentrations must be equal: $C_{	ext{urea}} = C_{	ext{sucrose}}$.First,calculate the molarity for each option.For option $A$: Molarity of urea $= \frac{3.0 \ g \ L^{-1}}{60 \ g \ mol^{-1}} = 0.05 \ mol \ L^{-1}$.Molarity of sucrose $= \frac{17.19 \ g \ L^{-1}}{342 \ g \ mol^{-1}} = 0.05026 \ mol \ L^{-1} \approx 0.05 \ mol \ L^{-1}$.Since the molar concentrations are equal,the solutions are isotonic.

Which of the following pairs of solutions is isotonic? (Molar mass: urea $= 60 \ g \ mol^{-1}$,sucrose $= 342 \ g \ mol^{-1}$)

Similar Questions

As a result of osmosis,what happens to the volume of the solution?

Calculate the osmotic pressure of $0.03 \ mol$ of non-electrolyte solute dissolved in $0.1 \ dm^3$ of water at $300 \ K \ [R=0.0821 \ dm^3 \ atm \ mol^{-1} \ K^{-1}]$ (in $atm$)

Assuming complete ionisation,arrange the following solutions in order of increasing osmotic pressure.
$(a)$ $0.5 \ m \ Li_2SO_4$
$(b)$ $0.5 \ m \ KCl$
$(c)$ $0.5 \ m \ Al_2(SO_4)_3$
$(d)$ $0.1 \ m \ BaCl_2$

Which method is used to remove salt from sea water?

The process of getting fresh water from sea water is known as

Vedclass Test Series

Exam Paper Generator

Online Exam Module