Which of the following sets of species have s | vedclass

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(D) The bond order $(BO)$ is calculated using the formula: $BO = \frac{N_b - N_a}{2}$.For $N_2$ $(14 \ e^-)$: $BO = \frac{10 - 4}{2} = 3$.For $CO$ $(1

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$N_2, CO, NO^{+}$

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(D) The bond order $(BO)$ is calculated using the formula: $BO = \frac{N_b - N_a}{2}$.For $N_2$ $(14 \ e^-)$: $BO = \frac{10 - 4}{2} = 3$.For $CO$ $(14 \ e^-)$: $BO = \frac{10 - 4}{2} = 3$.For $NO^+$ $(14 \ e^-)$: $BO = \frac{10 - 4}{2} = 3$.Since $N_2$,$CO$,and $NO^+$ all have a bond order of $3$,they have similar bond orders.Therefore,the correct set is $(N_2, CO, NO^{+})$.

Which of the following sets of species have similar bond order?

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