Which one of the following will show geometri | vedclass

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Question

(C) For a molecule to exhibit geometrical isomerism,the groups attached to the double-bonded carbons must be different. In the case of cyclic compound

Vedclass · Accepted Answer

$3-$bromo$-1-$methylenecyclohexane

Vedclass · Answer

(C) For a molecule to exhibit geometrical isomerism,the groups attached to the double-bonded carbons must be different. In the case of cyclic compounds with an exocyclic double bond,the ring itself acts as a substituent. In option $C$,the structure is $3$-bromo-$1$-methylenecyclohexane. Here,the carbon at position $3$ of the cyclohexane ring is chiral,and the exocyclic double bond at position $1$ is attached to the ring. Because the ring is substituted at the $3$-position,the two paths around the ring from the double bond to the $3$-position are different. Thus,the groups on the double-bonded carbon are effectively different,allowing for cis-trans (geometrical) isomerism.

Which one of the following will show geometrical isomerism?

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