Which product is obtained from the reaction between $CH_3ONa$ and $(CH_3)_3CBr$?

Consider the following reaction. Which of the following bases will give the best yield of the alkene $(II)$ as the major product?

Benzene $\xrightarrow[{Anhy. AlCl_3}]{{CH_3Cl}} A \,$ $\xrightarrow[{hv}]{{Cl_2 (1 \, mole)}} B$ $\xrightarrow{{AgCN}} C$
Which is correct for the above reaction?

When alcoholic $KOH$ is reacted with $CH_3CH_2Cl$ to form an alkene,which species acts as the attacking reagent?

Reaction $(A)$:
$Ph-CH=CH-CH_3 \xrightarrow[H_2O_2 / OH^-]{B_2H_6 / THF}$ products.
Reaction $(B)$:
$CH_3-CH=CH-Ph \xrightarrow[NaBH_4]{Hg(OAc)_2 / H_2O}$ products.
Correct statement is:

Predict all the alkenes that would be formed by dehydrohalogenation of the following halides with sodium ethoxide in ethanol and identify the major alkene:
$(i)$ $1-$Bromo$-1-$methylcyclohexane
$(ii)$ $2-$Chloro$-2-$methylbutane
$(iii)$ $2,2,3-$Trimethyl$-3-$bromopentane.