With the help of the remainder theorem,find t | vedclass

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(C) According to the remainder theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,the divisor is $x + 6$,which can be

Vedclass · Accepted Answer

$0$

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(C) According to the remainder theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,the divisor is $x + 6$,which can be written as $x - (-6)$.Therefore,we need to find $p(-6)$.Given $p(x) = x^{3} + x^{2} - 26x + 24$.Substituting $x = -6$ into the polynomial:$p(-6) = (-6)^{3} + (-6)^{2} - 26(-6) + 24$$p(-6) = -216 + 36 + 156 + 24$$p(-6) = -216 + 216$$p(-6) = 0$.Thus,the remainder is $0$.

With the help of the remainder theorem,find the remainder when the polynomial $p(x) = x^{3} + x^{2} - 26x + 24$ is divided by the divisor $x + 6$.

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