With what velocity an observer should move re | vedclass

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(D) The Doppler effect formula for an observer moving towards a stationary source is given by $n^{\prime} = n \left( \frac{v + v_{o}}{v} \right)$,wher

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Same as velocity of sound towards the source.

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(D) The Doppler effect formula for an observer moving towards a stationary source is given by $n^{\prime} = n \left( \frac{v + v_{o}}{v} \right)$,where $n^{\prime}$ is the observed frequency,$n$ is the source frequency,$v$ is the speed of sound,and $v_{o}$ is the velocity of the observer.Given that the observed frequency is double the source frequency,we have $n^{\prime} = 2n$.Substituting this into the formula: $2n = n \left( \frac{v + v_{o}}{v} \right)$.Dividing both sides by $n$: $2 = \frac{v + v_{o}}{v}$.Multiplying by $v$: $2v = v + v_{o}$.Solving for $v_{o}$: $v_{o} = v$.Therefore,the observer must move towards the source with a velocity equal to the speed of sound.

With what velocity an observer should move relative to a stationary source so that a sound of double the frequency of the source is heard by the observer?

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