$HCl$ does not show the peroxide effect because the reaction mechanism involves the following steps:
$CH_3-CH=CH_2 + \dot{X} \to CH_3-\dot{C}H-CH_2X$ $(I)$
$CH_3-\dot{C}H-CH_2X + HX \to CH_3-CH_2-CH_2X + \dot{X}$ $(II)$
Why does $HCl$ fail to undergo this reaction?

  • A
    $I$ and $II$ both steps are endothermic
  • B
    $I$ is exothermic and $II$ is endothermic
  • C
    $I$ is endothermic and $II$ is exothermic
  • D
    $I$ and $II$ both are exothermic steps

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