$\left[\frac{1}{1 \times 2}+\frac{1}{2 \times 3}+\frac{1}{3 \times 4}+\cdots+\frac{1}{99 \times 100}\right]$ is equal to

  • A
    $\frac{1}{9900}$
  • B
    $\frac{99}{100}$
  • C
    $\frac{100}{99}$
  • D
    $\frac{1000}{99}$

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