If $\tan ^{2} \theta = \sin ^{2} \theta + \cos ^{2} \theta$ and $0 < \theta < 90^{\circ}$,then the value of $\theta$ is ...... (in $^{\circ}$)

$\sin (90^\circ - \theta) = \ldots \ldots \ldots$

If $3 \theta$ is the measure of an acute angle and $\sin 3 \theta = \cos (\theta - 26^{\circ})$,then the value of $\theta$ is $\ldots \ldots \ldots \ldots$ (in $^{\circ}$)

In $\Delta ABC$,$m \angle B = 90^{\circ}$,$BC = 3$ and $AC = 5$,then $\tan A = \ldots$

For $0 < \theta < 90^{\circ},$ the value of $\ldots \ldots \ldots \ldots$ increases as $\theta$ increases from $0^{\circ}$ to $90^{\circ}$.

For acute angle $\theta,$ if $\cos \theta = \sin \theta,$ then $2 \tan^{2} \theta + \sin^{2} \theta + 1 = \ldots$