p rightarrow sim q can also be written as | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) We know that the implication $A \rightarrow B$ is logically equivalent to $\sim A \vee B$.Applying this rule to $p \rightarrow \sim q$,we get:$p \

Vedclass · Accepted Answer

$\sim p \vee \sim q$

Vedclass · Answer

(B) We know that the implication $A \rightarrow B$ is logically equivalent to $\sim A \vee B$.Applying this rule to $p \rightarrow \sim q$,we get:$p \rightarrow \sim q \equiv \sim p \vee \sim q$.This can also be verified using the truth table:| $p$ | $q$ | $\sim p$ | $\sim q$ | $p \rightarrow \sim q$ | $\sim p \vee \sim q$ ||---|---|---|---|---|---|| $T$ | $T$ | $F$ | $F$ | $F$ | $F$ || $T$ | $F$ | $F$ | $T$ | $T$ | $T$ || $F$ | $T$ | $T$ | $F$ | $T$ | $T$ || $F$ | $F$ | $T$ | $T$ | $T$ | $T$ |Since the truth values of $p \rightarrow \sim q$ and $\sim p \vee \sim q$ are identical for all possible truth values of $p$ and $q$,they are logically equivalent.

$p \rightarrow \sim q$ can also be written as

Similar Questions

If $(p \wedge \sim r) \rightarrow (\sim p \vee q)$ has a truth value of $False$,then the truth values of $p, q, r$ are respectively:

The Boolean expression $(\sim(p \wedge q)) \vee q$ is equivalent to

Which of the following pairs are not logically equivalent?

Negation of the statement $\forall x \in \mathbb{R}, x^2+1=0$ is

Which of the following sentences are statements? Give reasons for your answer.
The product of $(-1)$ and $8$ is $8.$

Vedclass Test Series

Exam Paper Generator

Online Exam Module