frac{d}{dx}({x^2} + cos x)^4 = | vedclass

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(C) To find the derivative of $({x^2} + \cos x)^4$,we use the chain rule.Let $u = {x^2} + \cos x$.Then the expression becomes $u^4$.The derivative wit

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$4({x^2} + \cos x)^3(2x - \sin x)$

Vedclass · Answer

(C) To find the derivative of $({x^2} + \cos x)^4$,we use the chain rule.Let $u = {x^2} + \cos x$.Then the expression becomes $u^4$.The derivative with respect to $x$ is given by $\frac{d}{dx}(u^4) = \frac{d}{du}(u^4) \cdot \frac{du}{dx}$.$\frac{d}{du}(u^4) = 4u^3$.$\frac{du}{dx} = \frac{d}{dx}({x^2} + \cos x) = 2x - \sin x$.Combining these,we get $4({x^2} + \cos x)^3 \cdot (2x - \sin x)$.

$\frac{d}{dx}({x^2} + \cos x)^4 = $

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