$\int_{ - \pi /2}^{\pi /2} {\frac{{\sin x}}{{1 + {{\cos }^2}x}}{e^{ - {{\cos }^2}x}}dx} $ का मान ज्ञात कीजिए।

  • A
    $2{e^{ - 1}}$
  • B
    $1$
  • C
    $0$
  • D
    इनमें से कोई नहीं

Explore More

Similar Questions

यदि $f(x) = f(2 - x)$ है,तो $\int_{0.5}^{1.5} xf(x) dx$ का मान क्या होगा?

$\int_0^{\pi /2} \frac{\sin^{3/2} x}{\cos^{3/2} x + \sin^{3/2} x} dx = $

$\frac{\int_{0}^{\pi/2} (x \cos x + 1) e^{\sin x} dx}{\int_{0}^{\pi/2} (x \sin x + 1) e^{\cos x} dx}$ का निरपेक्ष मान - के बराबर है।

$\int_{-4}^{4} (2^x + 2^{-x})(3^x + 3^{-x}) \, dx$ का मान ज्ञात कीजिए।

$\int_0^\pi {{e^{{{\cos }^2}x}}{{\cos }^5}3x} \,dx$ का मान है

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo