4 , g of copper is dissolved in concentrated | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The equivalent weight of an element is defined as the mass of the element that combines with $8 \, g$ of oxygen.Given that $4 \, g$ of $Cu$ produc

Vedclass · Accepted Answer

$32$

Vedclass · Answer

(B) The equivalent weight of an element is defined as the mass of the element that combines with $8 \, g$ of oxygen.Given that $4 \, g$ of $Cu$ produces $5 \, g$ of copper oxide.Therefore,$4 \, g$ of $Cu$ combines with $(5 - 4) = 1 \, g$ of oxygen.Using the unitary method:$1 \, g$ of oxygen combines with $4 \, g$ of $Cu$.So,$8 \, g$ of oxygen will combine with $\frac{4 	imes 8}{1} = 32 \, g$ of $Cu$.The equivalent weight of copper is $32 \, g \, eq^{-1}$.

$4 \, g$ of copper is dissolved in concentrated $HNO_3$. Upon strong heating of the resulting copper nitrate solution,$5 \, g$ of its oxide is obtained. The equivalent weight of copper is ...... .

Similar Questions

If the weight of $1 \ L$ of a gas is $2 \ g$,then its vapor density and molecular weight are respectively .....

The amount of $K_2Cr_2O_7$ (equivalent weight $49.04$) required to prepare $100 \ mL$ of its $0.05 \ N$ solution is ........ $g$.

The equivalent mass of a divalent metal is $31.82$. What is the mass of a single atom of this metal?

In $1 \ g$ of a metal oxide,the mass of metal precipitated is $0.68 \ g$. What is the equivalent weight of the metal?

The approximate mass of a tritium oxide molecule is $............$ $amu$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module