A bag contains 3 red and 3 white balls. If tw | vedclass

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(C) Let $R_1$ be the event that the first ball is red and $W_1$ be the event that the first ball is white.Let $R_2$ be the event that the second ball

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$3/5$

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(C) Let $R_1$ be the event that the first ball is red and $W_1$ be the event that the first ball is white.Let $R_2$ be the event that the second ball is red and $W_2$ be the event that the second ball is white.We want to find the probability that the balls are of different colors,which means the outcomes are $(R_1, W_2)$ or $(W_1, R_2)$.The total number of balls is $6$.$P(R_1, W_2) = P(R_1) 	imes P(W_2 | R_1) = \frac{3}{6} 	imes \frac{3}{5} = \frac{9}{30} = \frac{3}{10}$.$P(W_1, R_2) = P(W_1) 	imes P(R_2 | W_1) = \frac{3}{6} 	imes \frac{3}{5} = \frac{9}{30} = \frac{3}{10}$.The total probability is $P(R_1, W_2) + P(W_1, R_2) = \frac{3}{10} + \frac{3}{10} = \frac{6}{10} = \frac{3}{5}$.

$A$ bag contains $3$ red and $3$ white balls. If two balls are drawn one after another,what is the probability that they are of different colors?

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