લક્ષની કિંમત શોધો: $\mathop {\text{Limit}}\limits_{x \to 4} \frac{(\cos \alpha)^x - (\sin \alpha)^x - \cos 2\alpha}{x - 4}$,જ્યાં $0 < \alpha < \frac{\pi}{2}$.

  • A
    $(\cos \alpha)^4 \ln(\cos \alpha) + (\sin \alpha)^4 \ln(\sin \alpha)$
  • B
    $-(\cos \alpha)^4 \ln(\cos \alpha) - (\sin \alpha)^4 \ln(\sin \alpha)$
  • C
    $(\cos \alpha)^4 \ln(\cos \alpha) - (\sin \alpha)^4 \ln(\sin \alpha)$
  • D
    $-(\cos \alpha)^4 \ln(\cos \alpha) + (\sin \alpha)^4 \ln(\sin \alpha)$

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$\mathop {\lim }\limits_{x \to 0} \frac{{\sin x - x}}{{{x^3}}} = $

$\mathop {\lim }\limits_{x \to 0} \frac{{{4^x} - {9^x}}}{{x({4^x} + {9^x})}} = $

$\mathop {\lim }\limits_{\alpha \to \pi /4} \frac{{\sin \alpha - \cos \alpha }}{{\alpha - \frac{\pi }{4}}} = $

$\mathop {\lim }\limits_{x \to 0} \frac{{\tan 2x - x}}{{3x - \sin x}} = $

$\lim _{x \rightarrow 0} \frac{\tan x - \sin x}{x^3}$ ની કિંમત શોધો.

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