A p-n junction diode is connected to a batter | vedclass

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(C) The $p-n$ junction diode is connected in forward bias as the positive terminal of the battery is connected to the $p$-side of the diode.In forward

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$1\, mA$

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(C) The $p-n$ junction diode is connected in forward bias as the positive terminal of the battery is connected to the $p$-side of the diode.In forward bias,the effective voltage across the external resistor $R$ is given by $V_{eff} = V_{battery} - V_{barrier}$.Given: $V_{battery} = 5.5\, V$,$V_{barrier} = 0.4\, V$,and $R = 5.1\, k\Omega = 5.1 	imes 10^3\, \Omega$.$V_{eff} = 5.5\, V - 0.4\, V = 5.1\, V$.Using Ohm's law,the current $I$ in the circuit is $I = \frac{V_{eff}}{R}$.$I = \frac{5.1\, V}{5.1 	imes 10^3\, \Omega} = 1 	imes 10^{-3}\, A = 1\, mA$.Therefore,the current in the circuit is $1\, mA$.

$A$ $p-n$ junction diode is connected to a battery of $emf$ $5.5\, V$ and external resistance $5.1\, k\Omega$. The barrier potential in the diode is $0.4\, V$. The current in the circuit is

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