A 20, text{litre} mixture of milk and water c | vedclass

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(B) The initial $20\, 	ext{litre}$ mixture contains milk and water in the ratio $3:2$. Thus,the amount of milk is $12\, 	ext{litres}$ and water is $

Vedclass · Accepted Answer

$9:1$

Vedclass · Answer

(B) The initial $20\, 	ext{litre}$ mixture contains milk and water in the ratio $3:2$. Thus,the amount of milk is $12\, 	ext{litres}$ and water is $8\, 	ext{litres}$.Step $1$: When $10\, 	ext{litres}$ of the mixture is removed,the amount of milk removed is $(3/5) 	imes 10 = 6\, 	ext{litres}$ and water removed is $(2/5) 	imes 10 = 4\, 	ext{litres}$. Remaining: $6\, 	ext{litres}$ milk and $4\, 	ext{litres}$ water. After adding $10\, 	ext{litres}$ of pure milk,the container has $6+10 = 16\, 	ext{litres}$ of milk and $4\, 	ext{litres}$ of water.Step $2$: When $10\, 	ext{litres}$ of this new mixture is removed,the ratio of milk to water is $16:4$,which is $4:1$. The amount of milk removed is $(4/5) 	imes 10 = 8\, 	ext{litres}$ and water removed is $(1/5) 	imes 10 = 2\, 	ext{litres}$. Remaining: $16-8 = 8\, 	ext{litres}$ milk and $4-2 = 2\, 	ext{litres}$ water. After adding $10\, 	ext{litres}$ of pure milk,the container has $8+10 = 18\, 	ext{litres}$ of milk and $2\, 	ext{litres}$ of water.The final ratio of milk to water is $18:2$,which simplifies to $9:1$.

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