$A$ galvanometer gives a full-scale reading of $50 \ mA$,when a potential difference across its terminals is $0.15 \ V$. It can be used as an ammeter of range $0 - 100 \ A$ by connecting a shunt resistance of: (in $\Omega$)

  • A
    $0.00075$
  • B
    $0.00045$
  • C
    $0.0015$
  • D
    $3$

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Similar Questions

By connecting a resistance of $980 \Omega$ in series with a galvanometer, it is converted into a voltmeter of a certain range. When the resistance of $470 \Omega$ is connected in series, the range is halved. The resistance of the galvanometer is (in $\Omega$)

$A$ galvanometer may be converted into an ammeter or a voltmeter. In which of the following cases will the resistance of the device so obtained be the largest?

$A$ voltmeter of $250 mV$ range having a resistance of $10 \Omega$ is converted into an ammeter of $250 mA$ range. The value of the necessary shunt is (nearly): (in $\Omega$)

The current sensitivity of a galvanometer can be increased by:
$(A)$ decreasing the number of turns
$(B)$ increasing the magnetic field
$(C)$ decreasing the area of the coil
$(D)$ decreasing the torsional constant of the spring
Choose the most appropriate answer from the options given below.

If $n$ represents the actual number of deflections in a converted galvanometer of resistance $G$ and shunt resistance $S$,then the total current $I$ when its figure of merit is $K$ will be:

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