$A$ metal wire has a resistance of $35 \,\Omega$. If its length is increased to double by drawing it,then its new resistance will be (in $\Omega$)

$A$ cylindrical resistor is connected to a battery with emf $5 \ V$. The resistance per unit length varies as $\rho(x) = \rho_0 \left(\frac{x}{L}\right)^\alpha$,where $\rho_0$ and $\alpha$ are constants and $x$ is the distance from one end of the resistor. The product $\rho_0 L$ is $10 \ \Omega$,where $L$ is the length of the resistor. If the thermal power generated by the resistor is $20 \ W$,then the value of $\alpha$ is:

Wires $A$ and $B$ have resistivities $\rho_A$ and $\rho_B$,where $\rho_B = 2 \rho_A$,and have lengths $l_A$ and $l_B$. If the diameter of wire $B$ is twice that of $A$ and the two wires have the same resistance,then the ratio $\frac{l_B}{l_A}$ is:

Identify the correct statement among the following.

An electric toaster has a resistance of $60 \ \Omega$ at room temperature $\left(27^{\circ} C\right)$. The toaster is connected to a $220 \ V$ supply. If the current flowing through it reaches $2.75 \ A$,the temperature attained by the toaster is around: (given $\alpha = 2 \times 10^{-4} /{ }^{\circ} C$) (in $^{\circ} C$)

The resistivity of a wire: