A particle is executing S.H.M. Then the graph | vedclass

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(A) For a particle executing $S.H.M.$,the acceleration $a$ is given by the equation $a = -\omega^2 x$,where $\omega$ is the angular frequency and $x$

Vedclass · Accepted Answer

$A$ straight line

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(A) For a particle executing $S.H.M.$,the acceleration $a$ is given by the equation $a = -\omega^2 x$,where $\omega$ is the angular frequency and $x$ is the displacement.This equation is of the form $y = mx$,which represents a straight line passing through the origin.Here,the slope of the line is $m = -\omega^2$,which is negative.Therefore,the graph of acceleration versus displacement is a straight line with a negative slope.

$A$ particle is executing $S.H.M.$ Then the graph of acceleration as a function of displacement is

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