$A$ slab consists of two parallel layers of two different materials of same thickness having thermal conductivities $K_1$ and $K_2$. The equivalent conductivity of the combination is

  • A
    $K_1 + K_2$
  • B
    $\frac{K_1 + K_2}{2}$
  • C
    $\frac{2K_1 K_2}{K_1 + K_2}$
  • D
    $\frac{K_1 + K_2}{2K_1 K_2}$

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