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(C) In a common-emitter configuration,the current gain $\beta$ is defined as the ratio of the change in collector current to the change in base curren

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(C) In a common-emitter configuration,the current gain $\beta$ is defined as the ratio of the change in collector current to the change in base current at a constant collector-emitter voltage $V_{CE}$.$\beta = \left( \frac{\Delta I_C}{\Delta I_B} ight)_{V_{CE}}$Given:$\Delta I_C = 10\, mA - 5\, mA = 5\, mA = 5 	imes 10^{-3}\, A$$\Delta I_B = 200\,\mu A - 100\,\mu A = 100\,\mu A = 100 	imes 10^{-6}\, A$Substituting these values into the formula:$\beta = \frac{5 	imes 10^{-3}}{100 	imes 10^{-6}}$$\beta = \frac{5 	imes 10^{-3}}{10^{-4}}$$\beta = 5 	imes 10^1 = 50$Thus,the current gain is $50$.

$A$ transistor is operated in common-emitter configuration at $V_{CE} = 2\, V$ such that a change in the base current from $100\,\mu A$ to $200\,\mu A$ produces a change in the collector current from $5\, mA$ to $10\, mA$. The current gain is

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