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(B) The acceleration of the truck is $a_t = 5 \ m/s^2$. The maximum acceleration the block can have due to friction is $a_{max} = \mu g = 0.2 	imes 1

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(B) The acceleration of the truck is $a_t = 5 \ m/s^2$. The maximum acceleration the block can have due to friction is $a_{max} = \mu g = 0.2 	imes 10 = 2 \ m/s^2$.Since the truck accelerates at $5 \ m/s^2$,the block will slip on the truck and move with a constant acceleration of $a_{max} = 2 \ m/s^2$ relative to the ground.For the first $1 \ s$,the velocity of the block with respect to the ground is $v = u + at = 0 + 2 	imes 1 = 2 \ m/s$.After $1 \ s$,the truck moves with a constant velocity,so the acceleration of the truck becomes $0$. The friction force also becomes $0$,and the block continues to move with the velocity it attained at $t = 1 \ s$,which is $2 \ m/s$.Thus,the velocity of the block increases linearly to $2 \ m/s$ in $1 \ s$ and then remains constant at $2 \ m/s$.

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