આપેલ લક્ષની કિંમત શોધો: $\mathop {\lim }\limits_{x \to 1} \frac{a x^{2}+b x+c}{c x^{2}+b x+a}$,જ્યાં $a+b+c \neq 0$.

  • A
    $1$
  • B
    $0$
  • C
    $-1$
  • D
    $\frac{a+b+c}{c+b+a}$

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જો $a, b$ અને $c$ ત્રણ ભિન્ન વાસ્તવિક સંખ્યાઓ હોય અને $\lim _{x \rightarrow \infty} \frac{(b-c) x^2+(c-a) x+(a-b)}{(a-b) x^2+(b-c) x+(c-a)}=\frac{1}{2}$ હોય,તો $a+2 c=$

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