Factorise 49 x^{2}-35 x+6. | vedclass

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Question

(A) To factorise the quadratic expression $49 x^{2}-35 x+6$,we use the splitting the middle term method.We need to find two numbers such that their pr

Vedclass · Accepted Answer

$(7 x-2)(7 x-3)$

Vedclass · Answer

(A) To factorise the quadratic expression $49 x^{2}-35 x+6$,we use the splitting the middle term method.We need to find two numbers such that their product is $49 	imes 6 = 294$ and their sum is $-35$.The two numbers are $-21$ and $-14$,since $(-21) 	imes (-14) = 294$ and $(-21) + (-14) = -35$.Now,rewrite the middle term:$49 x^{2}-21 x-14 x+6$Group the terms:$(49 x^{2}-21 x) - (14 x-6)$Factor out the common terms from each group:$7 x(7 x-3) - 2(7 x-3)$Finally,factor out the common binomial $(7 x-3)$:$(7 x-3)(7 x-2)$

Factorise $49 x^{2}-35 x+6$.

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