From $6.55 \ g$ of aniline,the maximum amount of acetanilide that can be prepared will be _ $\times 10^{-1} \ g$.

Product $(B)$ of this reaction is:

In the given reaction,the end product $(C)$ is:

In a reaction of aniline,a coloured product $C$ was obtained as shown below:
$A$ $\xrightarrow{NaNO_2/HCl} B$ $\xrightarrow{N,N-dimethylaniline, \text{cold}} C$
The structure of $C$ would be:

Convert:
$(i)$ $3-$Methylaniline into $3-$nitrotoluene.
$(ii)$ Aniline into $1,3,5-$tribromobenzene.

$A$ is a neutral organic compound $(M.F.: C_8H_9ON)$. On treatment with aqueous $Br_2 / HO^{(-)}$, $A$ forms a compound $B$ which is soluble in dilute acid. $B$ on treatment with aqueous $NaNO_2 / HCl$ $(0-5^{\circ}C)$ produces a compound $C$ which on treatment with $CuCN / NaCN$ produces $D$. Hydrolysis of $D$ produces $E$ which is also obtainable from the hydrolysis of $A$. $E$ on treatment with acidified $KMnO_4$ produces $F$. $F$ contains two different types of hydrogen atoms. The structure of $A$ is