Hybridisation state of $C$ in diamond is

Explain the shape of $sp$,$sp^2$,and $sp^3$ hybrid orbitals.

The correct order regarding the electronegativity of hybrid orbitals of carbon is

The correct order of increasing $s$-character (in percentage) in the hybrid orbitals of the following molecules/ions is: $(I) \, CO_3^{2-}$,$(II) \, XeF_4$,$(III) \, I_3^-$,$(IV) \, NCl_3$,$(V) \, BeCl_2$.

Match List-$I$ with List-$II$ :

$LIST$-$I$ (Hybridization)	$LIST$-$II$ (Orientation in Space)
$A$. $sp^3$	$I$. Trigonal bipyramidal
$B$. $dsp^2$	$II$. Octahedral
$C$. $sp^3 d$	$III$. Tetrahedral
$D$. $sp^3 d^2$	$IV$. Square planar

Choose the correct answer from the options given below :

What is the hybridization of the central atom in $NH_4^+$?