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(C) For any compound to be aromatic,all carbon atoms must be $sp^2$ hybridized,the molecule must be planar,and it must follow $H$ückel's rule.$H$ückel

Vedclass · Accepted Answer

$(i)$,$(ii)$ and $(iii)$

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(C) For any compound to be aromatic,all carbon atoms must be $sp^2$ hybridized,the molecule must be planar,and it must follow $H$ückel's rule.$H$ückel's Rule $\Rightarrow 4n + 2 = 	ext{number of delocalized } \pi	ext{-electrons } (n = 0, 1, 2, 3, \dots)$$(i)$ Naphthalene: $10 \pi	ext{-electrons}$ $\Rightarrow 4n + 2 = 10$ $\Rightarrow n = 2$ (Aromatic)$(ii)$ Anthracene: $14 \pi	ext{-electrons}$ $\Rightarrow 4n + 2 = 14$ $\Rightarrow n = 3$ (Aromatic)$(iii)$ Phenanthrene: $14 \pi	ext{-electrons}$ $\Rightarrow 4n + 2 = 14$ $\Rightarrow n = 3$ (Aromatic)All three compounds are planar,have $sp^2$ hybridized carbon atoms,and follow $H$ückel's rule.Therefore,all are aromatic compounds.Hence,the correct answer is option $C$.

Identify the polynuclear aromatic compounds that are aromatic from the given structures:
$(i)$ Naphthalene
(ii) Anthracene
(iii) Phenanthrene

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Identify the polynuclear aromatic compounds that are aromatic from the given structures:$(i)$ Naphthalene(ii) Anthracene(iii) Phenanthrene