If 8, 2 are the roots of {x^2} + ax + beta = | vedclass

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(D) Given that $8$ and $2$ are the roots of the quadratic equation ${x^2} + ax + \beta = 0$.Using the relation between roots and coefficients,the sum

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$9, 1$

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(D) Given that $8$ and $2$ are the roots of the quadratic equation ${x^2} + ax + \beta = 0$.Using the relation between roots and coefficients,the sum of roots is $8 + 2 = -a$,which gives $a = -10$.The product of roots is $8 	imes 2 = \beta$,which gives $\beta = 16$.Given that $3$ and $3$ are the roots of the quadratic equation ${x^2} + \alpha x + b = 0$.Using the relation between roots and coefficients,the sum of roots is $3 + 3 = -\alpha$,which gives $\alpha = -6$.The product of roots is $3 	imes 3 = b$,which gives $b = 9$.Now,substitute the values of $a$ and $b$ into the equation ${x^2} + ax + b = 0$:${x^2} - 10x + 9 = 0$.Factoring the quadratic equation:$(x - 9)(x - 1) = 0$.Therefore,the roots are $x = 9$ and $x = 1$.

If $8, 2$ are the roots of ${x^2} + ax + \beta = 0$ and $3, 3$ are the roots of ${x^2} + \alpha x + b = 0$,then the roots of ${x^2} + ax + b = 0$ are

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