જો $\int f(x) \cos x \, dx = \frac{1}{2} [f(x)]^2 + C$ અને $f(0) = 0$ હોય, તો $f'(0) = $

  • A
    $1$
  • B
    $-1$
  • C
    $0$
  • D
    $2$

Explore More

Similar Questions

વિધેયનું સંકલન કરો: $\frac{x+2}{\sqrt{x^{2}+2 x+3}}$

Difficult
View Solution

$\int \cos^{-3/7} x \sin^{-11/7} x \, dx = $

Difficult
View Solution

વાસ્તવિક સંખ્યાઓ $\alpha, \beta, \gamma$ અને $\delta$ માટે,જો $\int \frac{\left(x^{2}-1\right)+\tan ^{-1}\left(\frac{x^{2}+1}{x}\right)}{\left(x^{4}+3 x^{2}+1\right) \tan ^{-1}\left(\frac{x^{2}+1}{x}\right)} d x =\alpha \log _{e}\left(\tan ^{-1}\left(\frac{x^{2}+1}{x}\right)\right) +\beta \tan ^{-1}\left(\frac{\gamma\left(x^{2}-1\right)}{x}\right)+\delta \tan ^{-1}\left(\frac{x^{2}+1}{x}\right)+C$ જ્યાં $C$ એ સ્વૈચ્છિક અચળાંક છે,તો $10(\alpha+\beta \gamma+\delta)$ નું મૂલ્ય ....... છે.

વિધેયનું સંકલન કરો: $\frac{1}{\cos (x+a) \cos (x+b)}$

Difficult
View Solution

$\int_{\frac{1}{\sqrt[5]{31}}}^{\frac{1}{\sqrt[5]{242}}} \frac{1}{\sqrt[5]{x^{30}+x^{25}}} d x=$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo