If f(x) = mx + c,f(0) = 1,and f'(0) = 1,then | vedclass

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(C) Given the function $f(x) = mx + c$. Taking the derivative with respect to $x$,we get $f'(x) = m$. Given $f'(0) = 1$,substituting $x = 0$ into $f'(

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$3$

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(C) Given the function $f(x) = mx + c$. Taking the derivative with respect to $x$,we get $f'(x) = m$. Given $f'(0) = 1$,substituting $x = 0$ into $f'(x) = m$ gives $m = 1$. Given $f(0) = 1$,substituting $x = 0$ into $f(x) = mx + c$ gives $f(0) = m(0) + c = 1$,so $c = 1$. Thus,the function is $f(x) = 1x + 1 = x + 1$. To find $f(2)$,substitute $x = 2$ into the function: $f(2) = 2 + 1 = 3$.

If $f(x) = mx + c$,$f(0) = 1$,and $f'(0) = 1$,then find the value of $f(2)$.

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