यदि $\frac{3x + 4}{(x + 1)^2(x - 1)} = \frac{A}{(x - 1)} + \frac{B}{(x + 1)} + \frac{C}{(x + 1)^2}$ हो,तो $A = $

  • A
    $\frac{-1}{2}$
  • B
    $\frac{15}{4}$
  • C
    $\frac{7}{4}$
  • D
    $\frac{-1}{4}$

Explore More

Similar Questions

यदि $\frac{x^4+3 x+1}{(x+1)^2(x-1)}=A x+B+\frac{C}{x+1}+\frac{D}{(x+1)^2}+\frac{E}{x-1}$ है, तो $A+B+C+D+E=$

यदि $\frac{32x^2+186x}{(x^2+1)(x+5)}=\frac{37x+1}{x^2+1}+\frac{\lambda}{x+5}$ है,तो $\frac{\lambda}{2}$ का मान ज्ञात कीजिए।

यदि $\frac{3}{(x-1)(x^2+x+1)} = \frac{1}{x-1} - \frac{x+2}{x^2+x+1} = f_1(x) - f_2(x)$ और $\frac{x+1}{(x-1)^2(x^2+x+1)} = A f_1(x) + (B + \frac{D}{x-1}) f_2(x) + \frac{C}{(x-1)^2}$ है,तो $A+B+C+D$ का मान ज्ञात कीजिए।

यदि $\frac{x^3+3}{(x-3)^3}=a+\frac{b}{x-3}+\frac{c}{(x-3)^2}+\frac{d}{(x-3)^3}$ है, तो $(a+d)-(b+c)=$

जब $3x^5-4x^4+5x^3-3x^2+6x-8$ को $x^2+x-3$ से विभाजित किया जाता है,तो भागफल क्या है?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo