If a circle $C$ passing through the point $(4, 0)$ touches the circle $x^2 + y^2 + 4x - 6y = 12$ externally at the point $(1, -1)$,then the radius of $C$ is

  • A
    $2\sqrt{5}$
  • B
    $4$
  • C
    $5$
  • D
    $\sqrt{57}$

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