In a nuclear reactor,the activity of a radioactive substance is $2000 / s$. If the mean life of the products is $50 \text{ minutes}$,then in the steady power generation,the number of radionuclides is:

  • A
    $12 \times 10^5$
  • B
    $60 \times 10^5$
  • C
    $90 \times 10^5$
  • D
    $15 \times 10^5$

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$A$ radioactive element decays to form a stable nuclide. The graph representing the number of radioactive nuclei $(N)$ versus time $(t)$ is:

The activity $R$ of an unknown radioactive nuclide is measured at hourly intervals. The results found are tabulated as follows:
$t (h)$$0$$1$$2$$3$$4$
$R (MBq)$$100$$35.36$$12.51$$4.42$$1.56$

$(i)$ Plot the graph of $R$ versus $t$ and calculate the half-life from the graph.
$(ii)$ Plot the graph of $\ln \left( \frac{R}{R_0} \right)$ versus $t$ and obtain the value of the half-life from the graph.

$N$ atoms of a radioactive element emit $n$ alpha particles per second. The half-life of the element is:

Half-life is measured by

The ratio of the number of active nuclei in two different samples is $2:3$. Their half-lives are $2 \ hours$ and $3 \ hours$ respectively. After $12 \ hours$,the ratio of their activities will be:

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