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(A) The distance between the foci of an ellipse is given by $2ae = 6$,which implies $ae = 3$.The length of the minor axis is given by $2b = 8$,which i

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$\frac{3}{5}$

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(A) The distance between the foci of an ellipse is given by $2ae = 6$,which implies $ae = 3$.The length of the minor axis is given by $2b = 8$,which implies $b = 4$.Using the relation $b^2 = a^2(1 - e^2)$,we have $b^2 = a^2 - a^2e^2$.Substituting the values $b = 4$ and $ae = 3$:$4^2 = a^2 - (ae)^2$$16 = a^2 - 3^2$$16 = a^2 - 9$$a^2 = 25$,so $a = 5$.Since $ae = 3$ and $a = 5$,the eccentricity $e = \frac{ae}{a} = \frac{3}{5}$.

In an ellipse,the distance between its foci is $6$ and the minor axis is $8$. Then its eccentricity is:

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