In the following circuit,the reading in the a | vedclass

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(C) The reading of the ammeter represents the current flowing through the circuit.According to Ohm's law for a circuit containing a diode,the current

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$21.5$

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(C) The reading of the ammeter represents the current flowing through the circuit.According to Ohm's law for a circuit containing a diode,the current $I$ is given by:$I = \frac{V - V_{	ext{diode}}}{R}$Here,the supply voltage $V = 5 	ext{ V}$,the resistance $R = 200 	ext{ } \Omega$,and for a silicon diode,the forward voltage drop $V_{	ext{diode}} = 0.7 	ext{ V}$.Substituting these values into the formula:$I = \frac{5 	ext{ V} - 0.7 	ext{ V}}{200 	ext{ } \Omega}$$I = \frac{4.3 	ext{ V}}{200 	ext{ } \Omega} = 0.0215 	ext{ A}$Converting the current to milliamperes $(1 	ext{ A} = 1000 	ext{ mA})$:$I = 0.0215 	imes 1000 	ext{ mA} = 21.5 	ext{ mA}$Thus,the reading in the ammeter is $21.5 	ext{ mA}$.

In the following circuit,the reading in the ammeter is (in $mA$)

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