In the shown common emitter amplifier circuit,$\beta = 80$ and $V_{BE} = 0.7\,V$. The value of $R_C$ is:

The current gain of a transistor in common emitter configuration is $80$. The resistances in collector and base sides of the circuit are $5 \text{ k}\Omega$ and $1 \text{ k}\Omega$ respectively. If the input voltage is $2 \text{ mV}$, the output voltage is: (in $\text{ V}$)

The load resistance and the base-emitter voltage of a transistor in $CE$ configuration are $5 \ k\Omega$ and $0.02 \ V$ respectively. If the collector current is $2 \ mA$,then its voltage gain is

For a transistor,the current ratio $\beta_{dc}$ is defined as the ratio of:

In an $n-p-n$ transistor, the collector current is $28 \,mA$. If $80 \%$ of electrons reach the collector, its base current in $mA$ is

In an $NPN$ transistor, the collector current is $28 \text{ mA}$. If $80\%$ of the electrons emitted by the emitter reach the collector, what is the base current in $\text{mA}$ (in $\text{ mA}$)?