સંમેય વિધેયનું સંકલન કરો: $\frac{x}{(x-1)^{2}(x+2)}$

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ધારો કે $\frac{x}{(x-1)^{2}(x+2)} = \frac{A}{(x-1)} + \frac{B}{(x-1)^{2}} + \frac{C}{(x+2)}$.
બંને બાજુ $(x-1)^{2}(x+2)$ વડે ગુણતા:
$x = A(x-1)(x+2) + B(x+2) + C(x-1)^{2}$.
$x=1$ લેતા,$1 = B(1+2) \Rightarrow 3B = 1 \Rightarrow B = \frac{1}{3}$.
$x=-2$ લેતા,$-2 = C(-2-1)^{2} \Rightarrow 9C = -2 \Rightarrow C = -\frac{2}{9}$.
$x^{2}$ ના સહગુણકોની સરખામણી કરતા: $0 = A + C \Rightarrow A = -C = \frac{2}{9}$.
તેથી,$\frac{x}{(x-1)^{2}(x+2)} = \frac{2}{9(x-1)} + \frac{1}{3(x-1)^{2}} - \frac{2}{9(x+2)}$.
બંને બાજુ સંકલન કરતા:
$\int \frac{x}{(x-1)^{2}(x+2)} dx = \frac{2}{9} \int \frac{1}{x-1} dx + \frac{1}{3} \int (x-1)^{-2} dx - \frac{2}{9} \int \frac{1}{x+2} dx$.
$= \frac{2}{9} \log |x-1| + \frac{1}{3} \left( \frac{(x-1)^{-1}}{-1} \right) - \frac{2}{9} \log |x+2| + K$.
$= \frac{2}{9} \log \left| \frac{x-1}{x+2} \right| - \frac{1}{3(x-1)} + K$,જ્યાં $K$ એ સંકલનનો અચળાંક છે.

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