Let the function $f:R \to R$ be defined by $f(x) = 2x + \sin x, x \in R$. Then $f$ is

  • A
    One-to-one and onto
  • B
    One-to-one but not onto
  • C
    Onto but not one-to-one
  • D
    Neither one-to-one nor onto

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Similar Questions

Let $A=\{1,3,7,9,11\}$ and $B=\{2,4,5,7,8,10,12\}$. Then the total number of one-one maps $f: A \rightarrow B$,such that $f(1)+f(3)=14$,is:

If $f: Z \rightarrow N$ is defined by $f(n) = \begin{cases} 2n, & \text{if } n > 0 \\ 1, & \text{if } n = 0 \\ -2n-1, & \text{if } n < 0 \end{cases}$, then the function $f$ is:

Which one of the following functions is a bijection?

The function $f: C \rightarrow C$ defined by $f(x) = \frac{ax + b}{cx + d}$ for $x \in C$, where $bd \neq 0$, reduces to a constant function if:

If $f: R \rightarrow R$ is defined by $f(x) = \begin{cases} x+4 & \text{for } x < -4 \\ 3x+2 & \text{for } -4 \leq x < 4 \\ x-4 & \text{for } x \geq 4 \end{cases}$ then the correct matching of List-$I$ from List-$II$ is:
List-$I$ List-$II$
$(A)$ $f(-5) + f(-4)$ $(i)$ $14$
$(B)$ $f(|f(-8)|)$ $(ii)$ $4$
$(C)$ $f(f(-7) + f(3))$ $(iii)$ $-11$
$(D)$ $f(f(f(f(0)))) + 1$ $(iv)$ $-1$
$(v)$ $1$
$(vi)$ $0$

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