Molar conductivity of $0.01 \ M$ $HCl$ solution is $400.0 \ \Omega^{-1} \ cm^{2} \ mol^{-1}$. Calculate the conductivity of $HCl$ solution.
- A$4.0 \times 10^{-4} \ \Omega^{-1} \ cm^{-1}$
- B$8.0 \times 10^{-2} \ \Omega^{-1} \ cm^{-1}$
- C$2.5 \times 10^{-2} \ \Omega^{-1} \ cm^{-1}$
- D$4.0 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$
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