Nickel combines with a uninegative monodentat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The central metal ion is $Ni^{2+}$, which has an electronic configuration of $[Ar] 3d^8$.Since the complex $[NiX_4]^{2-}$ is paramagnetic and has

Vedclass · Accepted Answer

$sp^3$, two

Vedclass · Answer

(A) The central metal ion is $Ni^{2+}$, which has an electronic configuration of $[Ar] 3d^8$.Since the complex $[NiX_4]^{2-}$ is paramagnetic and has a coordination number of $4$, it adopts a tetrahedral geometry.In a tetrahedral geometry, the hybridisation is $sp^3$.For $Ni^{2+}$ $(3d^8)$, the $3d$ orbitals have two unpaired electrons.Therefore, the hybridisation is $sp^3$ and the number of unpaired electrons is $2$.

Nickel combines with a uninegative monodentate ligand $(X^{-})$ to form a paramagnetic complex $[NiX_4]^{2-}$. The hybridisation involved and the number of unpaired electrons present in the complex are respectively:

Similar Questions

Which of the following statements is correct?

What is the coordination number of the central metal ion if it forms an octahedral complex?

Which of the following complexes does not match with the hybridization state of its metal ion?
$(i) [Ni(CO)_4], sp^3$
$(ii) [Ni(CN)_4]^{2-}, sp^3$
$(iii) [CoF_6]^{3-}, d^2sp^3$
$(iv) [Fe(CN)_6]^{3-}, sp^3d^2$

Which ion has tetrahedral geometry:

Which one of the following is an outer orbital complex and exhibits paramagnetic behaviour?

Vedclass Test Series

Exam Paper Generator

Online Exam Module