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(A) If two vectors $\vec{A}$ and $\vec{B}$ are mutually perpendicular,the angle $	heta$ between them is $90^{\circ}$.The scalar product (dot product)

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(A) If two vectors $\vec{A}$ and $\vec{B}$ are mutually perpendicular,the angle $	heta$ between them is $90^{\circ}$.The scalar product (dot product) of two vectors is given by the formula $\vec{A} \cdot \vec{B} = AB \cos 	heta$.Substituting $	heta = 90^{\circ}$ into the formula,we get $\vec{A} \cdot \vec{B} = AB \cos 90^{\circ}$.Since $\cos 90^{\circ} = 0$,the scalar product becomes $\vec{A} \cdot \vec{B} = AB 	imes 0 = 0$.Therefore,the scalar product of two mutually perpendicular vectors is $0$.

Column $I$	Column $II$
$(A) (A+B)$	$(p)$ North-east
$(B) (A-B)$	$(q)$ Vertically upwards
$(C) (A \times B)$	$(r)$ Vertically downwards
$(D) (A \times B) \times (A \times B)$	$(s)$ None

Obtain the scalar product of two mutually perpendicular vectors.

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