Solve the following system of inequalities graphically: $x+y \geq 4, 2x-y > 0$.

(N/A) $x+y \geq 4$ ..... $(1)$
$2x-y > 0$ ..... $(2)$
The graph of the lines,$x+y=4$ and $2x-y=0$,are drawn in the figure below.
Inequality $(1)$ represents the region above the line,$x+y=4$ (including the line $x+y=4$).
It is observed that $(1,0)$ does not satisfy the inequality $2x-y > 0$ as $2(1)-0 = 2 > 0$,so we test a point like $(0,1)$ which gives $2(0)-1 = -1 < 0$. Thus,the region for $2x-y > 0$ is the half-plane containing $(1,0)$ (since $2(1)-0 = 2 > 0$).
Hence,the solution of the given system of linear inequalities is represented by the common shaded region including the points on line $x+y=4$ and excluding the points on line $2x-y=0$.