The contrapositive of $\sim q \to p$ is equivalent to

  • A
    $p \to q$
  • B
    $p \wedge q$
  • C
    $p \vee q$
  • D
    $\sim p \to \sim q$

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The correct logical equivalences from the following are:
$(I)$ $p \to (q \to r) \equiv (p \land q) \to r$
$(II)$ $(p \to q) \to r \equiv p \to (q \lor r)$
$(III)$ $(p \to q) \to r \equiv (p \to r) \land (\sim q \to r)$
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