The current sensitivity of a moving coil galv | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The current sensitivity of a moving coil galvanometer is given by $I_s = \frac{NBA}{C}$,where $N$ is the number of turns,$B$ is the magnetic field

Vedclass · Accepted Answer

$+25$

Vedclass · Answer

(A) The current sensitivity of a moving coil galvanometer is given by $I_s = \frac{NBA}{C}$,where $N$ is the number of turns,$B$ is the magnetic field,$A$ is the area,and $C$ is the torsional constant.The voltage sensitivity is given by $V_s = \frac{I_s}{G}$,where $G$ is the resistance of the galvanometer coil.Given that the resistance $G$ is kept constant,the relationship between voltage sensitivity and current sensitivity is $V_s \propto I_s$.Since the current sensitivity $I_s$ increases by $25 \%$,the voltage sensitivity $V_s$ will also increase by $25 \%$ because the ratio $\frac{1}{G}$ is constant.Therefore,the percentage change in voltage sensitivity is $25 \%$.

Similar Questions

$A$ galvanometer has a resistance of $20\,\Omega$ and reads full-scale when $0.2\,V$ is applied across it. To convert it into a $10\,A$ ammeter,the galvanometer coil should have a

What is the value of shunt resistance required to convert a galvanometer of resistance $ 100 \Omega $ into an ammeter of range $ 1 \text{ A} $? Given: Full scale deflection of the galvanometer is $ 5 \text{ mA} $.

Only $4 \%$ of the total current in the circuit passes through a galvanometer. If the resistance of the galvanometer is $G$,then the shunt resistance connected to the galvanometer is:

$A$ $50\, \Omega$ galvanometer gets full-scale deflection when a current of $0.01\, A$ passes through the coil. When it is converted to a $10\, A$ ammeter,the shunt resistance is ........... $\Omega$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module