The intensity ratio of two waves is 1 : 16. T | vedclass

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(B) The intensity $I$ of a wave is directly proportional to the square of its amplitude $a$,i.e.,$I \propto a^2$.Given the ratio of intensities is $\f

Vedclass · Accepted Answer

$1:4$

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(B) The intensity $I$ of a wave is directly proportional to the square of its amplitude $a$,i.e.,$I \propto a^2$.Given the ratio of intensities is $\frac{I_1}{I_2} = \frac{1}{16}$.Using the relation $\frac{I_1}{I_2} = \left( \frac{a_1}{a_2} \right)^2$,we have $\left( \frac{a_1}{a_2} \right)^2 = \frac{1}{16}$.Taking the square root on both sides,we get $\frac{a_1}{a_2} = \sqrt{\frac{1}{16}} = \frac{1}{4}$.Therefore,the ratio of their amplitudes is $1:4$.

The intensity ratio of two waves is $1 : 16$. The ratio of their amplitudes is

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